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We use many strategies when trying to solve a math problem. What strategies would you use to solve this problem?

A can of candy worms had 3 red worms, 6 blue worms, and 5 green worms. Bike4Life decided to eat 2 of the green worms. After that what were the chances of pulling a blue worm out of the can?

Write an article and tell how you would solve this problem. Post your answer please when you figure it out.
Article posted January 7, 2008 at 10:13 AM • comment (6) • Reads 92 • Return to Blog List
 
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Posted Comments

3 red worms 6 blue worms 5
5-2=3 3+3=6+6=12
Posted January 11, 2008 at 12:05 PM by • Jigga
Posted January 11, 2008 at 12:05 PM by • Jigga
the answer is 6 out of twelve
Posted January 11, 2008 at 11:59 AM by • sparrow
Posted January 11, 2008 at 11:59 AM by • sparrow
I think that the answer is 6 chances to pull out of 9 candy worms.
Posted January 11, 2008 at 11:53 AM by • mguns
Posted January 11, 2008 at 11:53 AM by • mguns
its easyyou take 3 away from green and you'll have a 6 out of 12 chance
Posted January 11, 2008 at 11:48 AM by • legonut
Posted January 11, 2008 at 11:48 AM by • legonut
the answer is 6/12 because 5-2=3 and 3+3=6 and 6+6=12 and there is still 6 blue worms left
Posted January 11, 2008 at 11:47 AM by • salamiball
Posted January 11, 2008 at 11:47 AM by • salamiball
the anwser is 6 out of 12 because if you add them at first it would equal 14 and subtract 2 equals 12. and thats the anwser
Posted January 7, 2008 at 10:49 AM by • pollo
Posted January 7, 2008 at 10:49 AM by • pollo

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