Hello everyone! Hope your week has gone nicely!
Mine has been pretty interesting, because my brother had an English exchange student arrive on Thursday. He will be staying with us for the week, and I am really excited! English accents are so cool! This exchange trip has also reminded me that the end of the school year is really close! In order to prepare for the geometry final, I am going to tell you about a question we had to do for homework as a way to review.
This problem was on a worksheet I did recently involving the Law of Sines:
sinA = sinB
a b
A and B stand for angles of an oblique triangle, while a and b stand for the 2 sides opposite them. Basically, you can use this law to find one of these four measures, as long as you have an angle and the side opposite.
Basically, the problem was a triangle with angles A, B, and C, and sides a, b, and c. The measure of angle A was 35º, the measure of side a was 8 cm, and the measure of side b was 12 cm. The problem asked you to find the measure of angle B.
Through substitution, I came out with this equation:
sin(35) = sin(B)
8 12
By multiplying both sides by 12 and then by sin to the (-1), I was able to then solve for B:
sin-1(12sin(35)) = sin-1(sin(B))
8
m
This process took some time to get used to, but I've found I actually like this sorts of problems in trigonometry. Let me know if you have any questions! Have a great week! (:
Article posted June 10, 2012 at 07:54 PM •
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